How this calculation works
Select whether you need a complement, two independent events together, either independent event, or at least one occurrence across repeated trials. Enter probabilities as fractions from 0 to 1. These formulas combine supplied probabilities; the calculator does not estimate them from observations.
Worked example
This example uses illustrative inputs. Your current result is shown above.
For an event with p = 0.2 and three independent trials, no occurrence has probability 0.8³ = 0.512. At least once is 1 − 0.512 = 0.488, or 48.8%.
Assumptions and limits
- Enter 0.2 for 20%, not 20.
- The both/either modes assume independent events. Repeated trials also assume independence and the same p on each trial.
- “Either” includes cases where both occur; this is not an exclusive-or calculation.
Questions people ask
Can I use these formulas for dependent events?
Not without adjustment. If one outcome changes the chance of another, the joint probability requires conditional information that these fields do not collect.
Is “at least once” the same as exactly once?
No. At least once includes one, two or more successes. It is calculated by subtracting the chance of zero successes from one.